Find the electrostatic potential at a point on equatorial line of an electric dipole
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Consider an electric dipole consisting of 2 point charges −q−q and +q+q separated by a distance 2l2l . Let p be a point on a perpendicular bisector of a dipole at distance r from center O.
VQq+=14π∈0qBQVQq+=14π∈0qBQ
VQq−=14π∈0−qAQVQq−=14π∈0−qAQ
$V_Q= V_{P_{q+}}+V_{p_{q-}}V_Q= \large\frac{q}{4 \pi \in_0} \bigg[ \large\frac{1}{BQ}-\frac{1}{AQ} \bigg]V_Q=0BQ=AQ$
The net electrostatic potential at a point in the electric field due to an electric dipole at any point on the equatorial line is zero.
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VQq+=14π∈0qBQVQq+=14π∈0qBQ
VQq−=14π∈0−qAQVQq−=14π∈0−qAQ
$V_Q= V_{P_{q+}}+V_{p_{q-}}V_Q= \large\frac{q}{4 \pi \in_0} \bigg[ \large\frac{1}{BQ}-\frac{1}{AQ} \bigg]V_Q=0BQ=AQ$
The net electrostatic potential at a point in the electric field due to an electric dipole at any point on the equatorial line is zero.
(plz mark my answer as brainlist)
manglamarya786:
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Consider an electric dipole consisting of 2 point charges −q and +q separated by a distance 2l . Let p be a point on a perpendicular bisector of a dipole at distance r from center O.
VQq+=14π∈0qBQ
VQq−=14π∈0−qAQ
$V_Q= V_{P_{q+}}+V_{p_{q-}}V_Q= \large\frac{q}{4 \pi \in_0} \bigg[ \large\frac{1}{BQ}-\frac{1}{AQ} \bigg]V_Q=0BQ=AQ$
The net electrostatic potential at a point in the electric field due to an electric dipole at any point on the equatorial line is zero.
VQq+=14π∈0qBQ
VQq−=14π∈0−qAQ
$V_Q= V_{P_{q+}}+V_{p_{q-}}V_Q= \large\frac{q}{4 \pi \in_0} \bigg[ \large\frac{1}{BQ}-\frac{1}{AQ} \bigg]V_Q=0BQ=AQ$
The net electrostatic potential at a point in the electric field due to an electric dipole at any point on the equatorial line is zero.
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