Question

Find the elevation of the sun, if the length of a tower is √3/3 times the height of the tower

Answer 1

|\ A
| \
|  \ 
|   \
|    \
|     \
|      \
|       \
|        \
|         \
|_____\
B         C

This is a right angled triangle having right angle at B.
Here angle C is the angle of elevation of the sun .
AB = Height of the tower.
BC = length of the shadow of the tower,
Now ,
BC = √3 / 3 AB
Now in Δ ABC
tan C = AB / BC
tan C = AB / √3/3 * AB
∴ tan C = AB/ AB * 3 / √ 3
∴ tan C = √ 3
But , √3 = tan 60°
∴ tan C = tan 60°
∴ ∠ C = 60°

Therefore, the angle of elevation of the sun is 60°.