Question

find the energy in kwh consumed in 25 hours by two electric devices one of 100w and other of 500w​

Answer 1

The energy consumed by two device for 25 hour= 15 kwh

Step-by-step explanation:

Given two electric device one of 100w and other of 500 w

The energy consumed by two device for 25 hour

= (100×25 +500 × 25) watt-hour

= 15000 watt-hour

=(15000÷1000) kwh

=15 kwh

Answer 2

Energy consumed by electric device is 54000 kWh

Step-by-step explanation:

• Given data

        Time of duration = 25 h = 25×3600 (second)

• Power of electric device

        $\mathbf{\textrm{Power of one electric device} \ (V_{1})=100 W}$

        $\mathbf{\textrm{Power of one electric device} \ (V_{2})=500 W}$

       $\mathbf{\textrm{ Energy consume by electric device} \ (E_{1})=100\times 25\times 3600 (Wh)}$

• $\mathbf{\textrm{ Energy consume by second electric device} \ (E_{2})=V_{2}\times time}$

        $\mathbf{\textrm{ Energy consume by second electric device} \ (E_{2})=500\times 25\times 3600 \ (Wh)}$

• So

        $\mathbf{\textrm{total energy consume}\ (E)=E_{1}+E_{2}}$

        $\mathbf{\textrm{total energy consume}\ (E)=100\times 25\times 3600+500\times 25\times 3600}$

        $\mathbf{\textrm{total energy consume}\ (E)=25\times 3600(100+500) \ (Wh)}$

        $\mathbf{\textrm{total energy consume}\ (E)=25\times 3600\times 600 \ (Wh)}$

        $\mathbf{\textrm{total energy consume}\ (E)=\frac{25\times 3600\times 600}{1000} \ (kWh)}$

        $\mathbf{\textrm{total energy consume}\ (E)=25\times 360\times 6 \ (kWh)}$

        $\mathbf{\textrm{total energy consume}\ (E)=54000 \ (kWh)}$