Question

) Find the energy of the electron in the fifth Bohr orbit of the hydrogen atom. [Energy of the electron in the first Bohr orbit= -13.6 eV] (2 marks) ition​

Answer 1

Answer:

Grand state, n=1, energy is given by,

E1=−2.18×10−11ergs

Now, energy of the n=S (5th orbit} is given by,

Es=(S)2E1

=2S−2.18×10−11ergs

=−0.0872×10−11ergs

Energy required to go to the 5th orbit

=ES−E1

=−0.0872−(−2.18)×10−11ergs

=2.0928×10−11ergs

Now, 1erg=10−7J

⇒2.0928×10−11ergs=2.0928×10−18J

For wavelength, λ1=R[(1)21=(S)21]

where,