Question

find the equation for hyperbole whose vertices are (0,+-3) and eccentricity is 2​

Answer 1

Answer:Given a=3 and ae=5⇒e=  

3

5

​  

 

Using e  

2

=1+  

a  

2

 

b  

2

 

​  

 

9

25

​  

=1+  

9

b  

2

 

​  

⇒b  

2

=16

Therefore required hyperbola is,  

9

x  

2

 

​  

−  

16

y  

2

 

​  

=1

⇒16x  

2

−9y  

2

=144

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