Question

If height of an object is 3cm, what will be the position of the image of height 1.5cm formed after reflection from a concave mirror of focal length 8m?​

Answer 1

Answer:

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Explanation:

h1 = 3cm, u = -8cm, h2 = 4.5 (virtual image)

(i) we know that

m = h2/h1 = 4.5/3 = 1.5

and

m = - (v/u)

⇒ 1.5 = - (v/(-8))

⇒ v = 1.5 × 8 = 12 cm

We have,

1/v + 1/u = 1/f

⇒ 1/12 + 1/(-8) = 1/f

⇒ 1/f = 1/12 – 1/8 = (2 – 3)/24 = - (1/24)

∴ f = - 24 cm

(ii) v = 12 cm

So, the image is formed 12 cm behind the concave mirror.

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Answer 2

QUESTION:

If height of an object is 3cm, what will be the position of the image of height 1.5cm formed after reflection from a concave mirror of focal length 8m?

ANSWER:

HEIGHT OF AN OBJECT=3CM

HEIGHT OF THE IMAGE = 1.5CM

IN A MIRROR

MAGNIFICATION=

HEIGHT OF IMAGE÷HEIGHT OF OBJECT

=1.5÷3

=½

MAGNIFICATION IS ALSO = -V/U

=>-v/u=1/2

=>u=-2v

ACCORDING TO MIRROR FORMULA

1/v +1/u=1/f

1/v-1/2v= (-1/8)

1/v=(-1/8)

v=(-8)m

SO THE POSITION OF IMAGE IS 8M BEHIND THE MIRROR OR (-8)M