Question

Find the equation of a circle which touches the X-axis at a distance 3 from the origin and cuts

off an intercept of length 6 from the Y-axis.​

Answer 1

Answer:

Find the equation of a circle which touches the X-axis at a distance 3 from the origin and cuts

off an intercept of length 6 from the Y-axis

Answer 2

Answer:

Let O be the centre of axis of circle & × bisect the intercept AB(6 units) i.e XA=3units

In △XOA,OX ^2=XA^2=OA^2 [Pythagoras theorem]

⇒9+9=OA^2

OA= radius =

$\sqrt{18}$

Centre of circle +(3,3 ROOT 2)

Equation:

$(x - 3) ^{2} + (y - 3 \sqrt{2}) ^{2} = 18$