Question

find the equation of a circle whose center is 5, 3 and radius is 4

Answer 1

Step-by-step explanation:

(x-a)^2 + (y- b)^2 = r^2

a= 5

b= 3

r= 4

(x-5)^2 + (y-3)^2 = 16

Answer 2

Answer:

Given:

centre=(5,3) and radius = 4

(x-h)^2+(y-k)^2=r^2

p(x,y) (h,k)=(5,3). r=4

(x-5)^2+(y-3)^2=(4)^2

x^2+25-10x + y^2+9-6y = 16

x^2+y^2-10x-6y+34-16=0

x^2+y^2-10x-6y+18=0

hence ...

the required equation is x^2+y^2-10x-6y+18=0

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