Question

find the equation of a circle with Centre 3, 4 radius 5. solve step by step?​

Answer 1

Answer:

x^2 + y^2- 6x - 8y = 0

Step-by-step explanation:

center : (a, b)

radius : r

Equation : (x-a)^2 + (y-a)^2 = r^2

Now.....

(x-3)^2 + (y-4)^2 = 5^2

(x^2 - 6x + 9) + (y^2-8y + 16) = 25

x^2 + y^2- 6x - 8y = 0

Answer 2

Answer:

X2+y2-6x-8y=0

Step-by-step explanation:

(x-h)2+(y-k)2=r2

(x-3)2+(y-4)2=25

x2-6x+9+y2-8y+16=25

X2+y2-6x-8y=0