find the equation of a circle with centre (a,a) and radius √2
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Answered by
1
General equation of circle is
(x-a)²+(y-b)²=r²
Subtituting the value given;
So equation of circle will be
(x-a)²+(y-b)²=2 Answer
(x-a)²+(y-b)²=r²
Subtituting the value given;
So equation of circle will be
(x-a)²+(y-b)²=2 Answer
Anonymous:
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I know till this, but my answer is not coming. can you please solve it?
the answer is x²+y²-2ax-2ay=0
yup wait
do we have something more in the question
because my answer is x²+y²+2a²-2ax-2ay=2
no, there nothing more
Answered by
1
Hi ,
Equation of the circle whose centre
is ( a , b ) and radius = r is
( x - a ) ² + ( y - b ) ² = r²
According to the problem given ,
Centre = ( a , a ) ; r = √2
( x - a )² + ( y - a )² = ( √2 )²
x² - 2ax + a² + y² - 2ay + a² = 2
x² + y² - 2ax - 2ay + 2a² - 2 = 0
I hope this helps you.
:)
Equation of the circle whose centre
is ( a , b ) and radius = r is
( x - a ) ² + ( y - b ) ² = r²
According to the problem given ,
Centre = ( a , a ) ; r = √2
( x - a )² + ( y - a )² = ( √2 )²
x² - 2ax + a² + y² - 2ay + a² = 2
x² + y² - 2ax - 2ay + 2a² - 2 = 0
I hope this helps you.
:)
but the answer in the book is x²+y²-2ax-2ay=0
if the radius is √2 a then we get the answer
check the question
yup
I think the answer is wrong in the book then
yes
Thank you so much for helping^_^
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