Question

Find the equation of a circle with with A (2,-3)
and B(-3,5) as end points of its
diameter.
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Answer 1

Answer:

${x}^{2} + {y}^{2} + x - 2y - 21 = 0$

Step-by-step explanation:

$(x - 2)(x + 3) + (y + 3)(y - 5) = 0 \\ \\ {x}^{2} + x - 6 + {y}^{2} - 2y - 15 = 0 \\ \\ {x}^{2} + {y}^{2} + x - 2y - 21 = 0$