Question

Write a java program to find the area for the following. Area of rhombus =1/2*diagonal1*diagonal 2. Area of trapezium =1/2*height *(a+b). Area of circle =pie*r*r​

Answer 1

Answer:

// C++ program to calculate the area of a rhombus

// whose one side and one diagonal is given

#include<bits/stdc++.h>

using namespace std;

// function to calculate the area of the rhombus

double area(double d1, double a)

{

// Second diagonal

double d2 = sqrt(4 * (a * a) - d1 * d1);

// area of rhombus

double area = 0.5 * d1 * d2;

// return the area

return area;

}

// Driver code

int main()

{

double d = 7.07;

double a = 5;

printf("%0.8f", area(d, a));

}

Answer 2

import java.util.*;

public class Area

{

public static void main (String args[])

{

Scanner in= new scanner (System.in);

int d1,d2, h, a , b, rd;

double r, t, c;

System.out.println("enter the values of the diagonals of rhombus, the values of the parallel sides and height of trapezium and the radius of the circle :");

d1 = in.nextInt();

d2 = in.nextInt();

h = in.nextInt();

a = in.nextInt();

b = in.nextInt();

rd = in.nextInt();

r = (1/2*d1*d2);

t = (1/2*h*(a+b));

c = (22/7*r*r);

System.out.println("Area of rhombus = " +r );

System.out.println("Area of trapezium =" +t );

System.out.println("Area of circle =" +c);

}

}