Question

when a ball is thrown at an angle of 30degree with the horizontal it lands at a horizontal distance of 100m.what will be the horizontal range of a ball when it is trown at an angle of (a) 60 degree (b) 45 degree with the same velocityy

Answer 1

Answer:

the horizontal range of ball when fired at angle 60 is 100√3m or 173.2m.

And when 45 than 100√2 or 141m

Answer 2

(a) Range, R = 99.94 m

(b) Range, R = 115.4 m

Explanation:

It is given that, when a ball is thrown at an angle of 30 degrees with the horizontal it lands at a horizontal distance of 100 m. The formula of horizontal range is given by :

$R=\dfrac{u^2\sin 2\theta}{g}$

u is the speed of projection

If $\theta=30^{\circ}$, R = 100 m

$u=\sqrt{\dfrac{Rg}{\sin 2\theta}} \\\\u=\sqrt{\dfrac{100\times 9.8}{\sin 2(30)}} \\\\u=33.63\ m/s$

(a) If angle of projection is 60 degrees. Horizontal range is :

$R=\dfrac{33.63^2\times \sin 2(60)}{9.8}\\R=99.94\ m$

(b) If angle of projection is 45 degrees. Horizontal range is :

$R=\dfrac{33.63^2\times \sin 2(45)}{9.8}\\R=115.4\ m$

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