Question

find the equation of a line passing through (6,-2) and perpendicular to the line joining the points (6,7)and(2,-3)​

Answer 1

Answer:

2x+5y-2=0

Step-by-step explanation:

slope of line joining the points (6,7)&(2,-3) is 5/2.

Then slope of the line perpendicular to the line will be -2/5.

The line having slope -2/5 is passing through the point (6,-2).

Now, using one point and slope form of straight line equation we get

2x+5y-2=0

Answer 2

Answer:

Answer in attachment

hope it helps

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