Question

Find the equation of a line perpendicular to the line
x -2y +3 =0 and passing through the point (1, -2) . ​

Answer 1

answer is attached here

Answer 2

Answer:

y = -2x + 4

Step-by-step explanation:

x - 2y +3 = 0

2y = x + 3

y = x/2 + 3/2

slope m = 1/2

two line are perpendicular if

m1 * m = -1

M1 = -2

point p(1,2)

equation of line having slope -2 and point (1,2) are

y - y1= m(x - x1)

y - 2 = -2( x - 1)

y - 2 = -2x + 2

y +2x = 4

y = -2x + 4