Question

Find the equation of a line through the given pair of points (0, -6) and (-2, 12)​

Answer 1

Answer:

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Step-by-step explanation:

$so \: here \: \\ given \: points \: are \: (0, - 6) \: \: and \: \: ( - 2,12) \\ so \: let \: then \\ (x1,y1) = (0, - 6) \\ (x2,y2) = ( - 2,12) \\ \\ so \: we \: know \: that \\ two \: points \: form \: equation \: of \: staight \: line \: \\ is \: given \: by \\ \frac{y - y1}{y1 - y2} = \frac{x - x1}{x1 - x2} \\ \\ \frac{y - ( - 6)}{ - 6 - 12} = \frac{x - 0}{0 - ( - 2)} \\ \\ \frac{y + 6}{ - 18} = \frac{x}{ 2} \\ \\ 2(y + 6) = - 18x \\ 2y + 12 = - 18x \\ \\ 18x + 2y + 12 = 0 \\ dividing \: throughout \: by \: 2 \\ we \: get \\ \\ 9x + y + 6 = 0$

$hence \: the \: equation \: of \: a \: line \: through \: the \: \\ points \: (0, -6) \: and \: (-2, 12) \: is \\ 9x + y + 6 = 0$