Question

find the equation of a line which is perpendicular bisector to the line joining points (4,-3) (3,1)

Answer 1

Answer:

x-4y-15/2=0

Step-by-step explanation:

Equation of the line joining points (4,-3),(3,1) is:

(x-4)/(y+3)=(3-4)/(1+3)

⇨4x+y-13=0

The perpendicular line equation of 4x+y-13=0 is:

x-4y+k=0

as it is an bisector,it goes through ((4+3)/2,(-3+1)/2) or (7/2,-1) point.

so, 7/2+4+k=0

⇨k= -15/2

so the final equation is x-4y-15/2=0