Question

Find the equation of a line which passes through the point of intersection of lines x 2y

Answer 1

Answer:

don't know...................

Answer 2

Answer:

Step-by-step explanation:

x+3y−1=0(1)

x−2y+4=0(2)

Equation of a line passing through intersection of (1) and (2) is

A(x+3y−1)+B(x−2y+4)=0⟹

(A+B)x+(3A−2B)y−A+4B=0(3)

Equation of a line ⊥ to 3X+2y=0is

2x−3y+C=0(4)

From (1),(2) and (4)

A+B=2

3A−2B=−3

−A+4B=C

From these A=15;B=95 and C=7

So (4) becomes

2x−3y+7=0