Find the equation of a line whose y-intercept is – 3 and which is perpendicular to the line joining the points (0, – 5) and (– 1, 3).
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equation line is perpendicular to
3x+5y-8=0 is 5x-3y+d=0
Ang its intercept on x- axis at (-3,0)
5(-3)-3(0)+d=0
d=15
hence required equation is 5x-3y+15=0
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