Find the equation of a line with X intercept 3 and y intercept -5
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When x-intercept = 3 corresponding point on the x-axis = (3,0)
When y-intercept = -12 corresponding point on y-axis = (0,-5)
Let (3,0) = (x1,y1) and (0,-5) = (x2,y2)
slope = y2 - y1 = -5 - 0 = 5/3
x2 - x1 0 - 3
The required equation
y - y1 = m (x - x1)
y - 0 = 5/3 (x - 3)
y = 5x - 15
3
⇒5x - 3y = 15
When y-intercept = -12 corresponding point on y-axis = (0,-5)
Let (3,0) = (x1,y1) and (0,-5) = (x2,y2)
slope = y2 - y1 = -5 - 0 = 5/3
x2 - x1 0 - 3
The required equation
y - y1 = m (x - x1)
y - 0 = 5/3 (x - 3)
y = 5x - 15
3
⇒5x - 3y = 15
Answered by
4
Hey !!
Check the attachment.
Hope it helps :)
Check the attachment.
Hope it helps :)
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