Question

Find the equation of a straight line passing through (4,3) and having slope 3
1) y-2x+4=0
2) y-2x-450
3) y+2x+4=0
4) y+2x-4=0
O 2
O 3
O4​

Answer 1

Answer:

We know that the equation of line passing through point (x0,y0) whose slope is m is

(y−y0)=m(x−x0)

Thus the equation of line passing through the point (−4,3) whose slope is 21 is,

(y−3)=21(x+4)

⇒2(y−3)=(x+4)

⇒x−2y+10=0