Question

Find the equation of a straight line passing through (-8,4) and making equal intercepts on the coordinate axes​

Answer 1

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Answer 2

Equation of a straight lines passing through (-8,4) making equal intercept on the co-ordinate axis.

As we know that,

Let we assume that x-intercept & y-intercept = t

equation of line,

→ x/a + y/b = 1.

• We can write as,

$\sf \implies \: \frac{x}{t} + \frac{y}{t} = 1 \\\\\\\sf \implies \: \frac{ - 8}{t} + \frac{4}{t} = 1 \\\\\\\sf \implies \: -8 + 4 = t \\\\ \\\sf \implies \: -4 = t.$

• Put the value of t = -4 in equation, we get.

$\sf \implies \frac{x}{ - 4} + \frac{y}{ - 4} = 1 \\\\\\ \sf \implies x + y = -4 \\\\\\ \sf \implies x + y + 4 = 0.$

MORE INFORMATION

Equation of straight lines parallel to axes.

• Equation of x-axis ⇒ y = 0.
• Equation of a line parallel to x-axes at a distance of b → y = b.
• Equation of y-axis ⇒ x = 0.
• Equation of a line parallel to y-axes and at a distance of a ⇒ x = a.