Find the equation of a straight line passing through the point (-1,1) with y-intercept -4
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Answer:
see the explanation beta.
Step-by-step explanation:
Given, a line equation passes through point (2,−5) and makes a y- intercept of −3
We know that,
The equation of line is y=mx+c, where m is the slope and c is the y intercept
So, we have
y=mx−3
Now, this line equation will satisfy the point (2,−5)
−5=m(2)−3
−5=2m−3
2m=3−5=−2
⇒m=−1
Hence, the equation of the line is y=−x+(−3)⇒x+y+3=0
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