find the equation of a straight line perpendicular to the line 3x-4y+12=0 and having same y intercept as 2x-y+5=0.
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eqn of line perpendicular to the given line is -3x-4y+c=0..................•{product of slope=-1}•
Now put X =0 in 2x-y+5=0..y=5
put x=0 and y=5 in -3x-4y+c=0 u will get c=20
••••[so the ans is -3x+4y+20=0]•••••
Now put X =0 in 2x-y+5=0..y=5
put x=0 and y=5 in -3x-4y+c=0 u will get c=20
••••[so the ans is -3x+4y+20=0]•••••
saurabhsemalti:
sorry,, that is -4ynot +4y
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