Find the equation of a straight line perpendicular to the line 2x + 5y + 7 = 0 and with
y-intercept -3.
Answers
Answered by
5
Answer:
m slope =-2/5 so m1 slope =5/2 since perpendicular mm1=-1
equation of the line therefore
y-3=5/2(x-0 )
2y -5x-6 =0
Answered by
3
Answer:
5x-2y-6=0
Step-by-step explanation:
y=-1/m x+ c
here c= -3 given and m= -a/b =>-2/5
y= 5/2x-3
2y=5x-6
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