Find the ordinary and general equation and draw the graph of the Parabola, according to the Following data: b) Vertex (-4; 2); focal axis: y = 2; passes through the point (0; 6)
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Step-by-step explanation:
The graph of a quadratic equation in the form y=ax2+bx+c has as its axis of symmetry the line x=−b2a . So, the equation of the axis of symmetry of the given parabola is x=−(−7)2(1) or x=72 . Substitute x=72 in the equation to find the y -coordinate of the vertex.
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