Question

find the equation of a straight line which passes through the point (1,-2) and cuts off equal intercepts from axes

Answer 1

Answer:

x+y+1=0

Step-by-step explanation:

We know, Intercept form of line is

x/a + y/b = 1

where, a and b are the intercept cut on x and y axis respectively.

Given, a=b

Equation becomes x/a + y/a = 1.....(i)

Now, it passes through (1,-2). So (1,-2) must satisfy (i).

1/a + (-2)/a = 1

-1/a = 1

a = -1

Putting in (i),

x/(-1) + y/(-1) = 1

x + y = -1

So, x+y+1=0 is equation of required line.

If you like the answer, please mark it as the brainliest answer.