Question

Find the equation of a straight line which passes through origin and making an angle 60° with the line x+√3y+5=0
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Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

x+√3y+5=0

√3y= -x -5

y= (-1/√3)x -5/√3

therefore, m= -1/√3

tan 60 = | M2 - M1 /1 + M2M1|

by putting the value in this you the can find the slope of another line

then put the value of slope in (y-y1) = m(x -x1).

you can find your answer