Question

find the equation of a straight line with Scope -3/2 and which intersect x axis at a distance of 4 unit to the left of the origin​

Answer 1

Answer:

intersect x axis at point (4, 0)

m=-3/2

y=mx+c

0= -3/2(4) +c

c=6

y= -3/2 (x) +6

whole eqn multiplied by 2

(y= -3/2 (x) +6)2

2y= -3x+12 is the st. line needed