Question

find the equation of a straiht linewhose slope is -3 and y intercept is 4​

Answer 1

ANSWER

We have,

slope=−4 and points (1,2)

We know that the equation of the line which is passing through the points

y−y

1

=slope(x−x

1

)

So,

y−2=−4(x−1)

y−2=−4x+4

4x+y−6=0

Hence, this is the answer.

Answer 2

Let m1 be the slope of a line

•°• m1 = -3

y intercept is 4 i.e c = 4

Equation of line

y = mx + c ... { slope - intercept}

y = -3(x) + 4 •°• y = -3x + 4

3x + y - 4 = 0 is the Equation of straight line.