find the equation of a straitht line passing through the point p(-5,2) and parallel to the line joining the points Q(3,-2) and R(-5,4)
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Answer:
4y+3x+7
Step-by-step explanation:
let the line be AB
when two lines are parallel there slope is same
Q(3,-2)=Q(x,y) &. R(-5,4)=R(x',y')
Slope of QR(M)= (y'-y)÷(x'-x)
=(4-(-2))÷(-5-3)
=6÷(-8)
= -3/4.......
Slope of line AB(M')= -3/4
P(-5,2)=P(x",y") is point on AB
.......,Equation of line of AB
(y - y") = M'(x - x")
y-2= -3/4(x-(-5))
4y-8=-3x-15
4y+3x+7......
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