Question

Find the equation of circle if Centre is (a cos α, a sin α) and radius is 2a
1 point

Answer 1

SOLUTION

TO DETERMINE

The equation of circle if Centre is (a cos α, a sin α) and radius is 2a

CONCEPT TO BE IMPLEMENTED

The equation of circle if Centre is (a, b) and radius r unit is

$\sf{ {(x - a)}^{2} + {(y - b)}^{2} = {r}^{2} }$

EVALUATION

Here we have to find the equation of circle if Centre is (a cos α, a sin α) and radius is 2a

Hence the required equation of the circle is

$\sf{ {(x - a \cos \alpha )}^{2} + {(y - a \sin \alpha )}^{2} = {(2a)}^{2} }$

$\sf{ \implies \: {(x - a \cos \alpha )}^{2} + {(y - a \sin \alpha )}^{2} = 4{a}^{2} }$

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