Question

find the equation of circle lying in 1st quadrant touching both the coordinate axes and the line X+Y=2​

Answer 1

Answer:

The circle touches the x and y axes at (1,0) and (0,1) respectively.

Since tangents are perpendicular to radii at the points of contact, its center must be at the point (1,1). Clearly, its radius is one unit.

So the equation of the circle is

(x−1)

2

+(y−1)

2

=1

⇒x

2

+y

2

−2x−2y+1=0

Step-by-step explanation:

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