Question

Find the equation of circle passing through (1,1),(2,-1),(3,2)​

Answer 1

Answer:

x² + y² - 5x - y + 4 = 0

Step-by-step explanation:

equation of the line passing (2,-1),(3,2)​ is 3x-y-4=0

(x-2)(x-3) + (y+1)(y-2) - λ(3x-y-4) = 0

substitute the 3rd point (1,1) to find the parameter λ

2 - 2 + 2λ = 0    ,   λ = 0

the equation of the circle is

(x-2)(x-3) + (y+1)(y-2) = 0

x² + y² - 5x - y + 4 = 0