find the equation of Circle passing through (-3,1) (6,4) and (2,-6)
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Answer:
x
2
+y
2
+2gy+2fy+c=0
passing from (1,2) then
1+4+2g+4f+c=0
=2g+4f+c=−5(1)
from(3,−4)
9+16+8f+c=0
6g−8f+c=−25(2)
from(5,−6)
25+36+10g−12f+c=0
10g−12f+c==61(3)
on substituting equation (1) and (2)
hence, we have
−4g+12f=20
−g+3f=5(4)
on substituting equation 2 and 3
we get
−4g+4f=36
−g+f=9(5)
on substituting equation 4 and 5
we get
2f=−4
f=−2
∴g==11
and c=25
putting in the equation
we get
x
2
+y
2
−22x−4f+25=0
Step-by-step explanation:
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