Question

find the equation Of circle passing through the point (4,1)and (6,5)and whose centre is on the line 4x+y=16
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Answer 1

Answer:

solved

Step-by-step explanation:

let A = (4,1)and B = (6,5)

mid point of AB = ( 5,3  )

equation of perpendicular bisector is y-3 = (x-5)/4 ,  y= (x-5)/4 +3  = x/4 + 7/4

solving with 4x+y=16

the centre of the circle is ( 57/4 ,16  )

equation Of circle

(x-57/4)² + (y-16)² = (6 -57/4)² + (5-16)²

x²-57x/2 + y² - 32y = 6²-57(3 )+ 5² - 32(5)  

x² + y² -57x/2 - 32y +270 = 0