Find the equation of circle with centre (0 0) and radius 3
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Equation of circle--
(x -a)² + (y - b)² = r²
Here a = 0 and b = 0,
So, (x - 0)² + (y - b)² = 3²
x² + y² = 9
Required answer - x² + y² = 9
Hope This Helps You!
(x -a)² + (y - b)² = r²
Here a = 0 and b = 0,
So, (x - 0)² + (y - b)² = 3²
x² + y² = 9
Required answer - x² + y² = 9
Hope This Helps You!
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