find the equation of circle with centre(1,0) and passing through the point P(3,1.5)
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Heya User,
--> We apply the formula :-> x² + y² = r²
Hence,
---> Here, ( x - 1 )² + y² = r² ----> (i)
Now, r = Distance b/w Center and the point
---> r = √(4 + 2.25) = √6.25 = 2.5
Hence, from (i) it follows :->>
--> (x-1)² + y² = 6.25
--> x² - 2x + 1 + y² = 6.25
--> x² - 2x + y² - 5.25 = 0 <--- Is therefore the Equation of the circle.....
--> We apply the formula :-> x² + y² = r²
Hence,
---> Here, ( x - 1 )² + y² = r² ----> (i)
Now, r = Distance b/w Center and the point
---> r = √(4 + 2.25) = √6.25 = 2.5
Hence, from (i) it follows :->>
--> (x-1)² + y² = 6.25
--> x² - 2x + 1 + y² = 6.25
--> x² - 2x + y² - 5.25 = 0 <--- Is therefore the Equation of the circle.....
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