Question

find the equation of circle with centre(-3,2) and radius 5.

Answer 1

Answer:

x^2+y^2+6x-4y=12

Step-by-step explanation:

As we know,

(x-h)^2+(y-k)^2=r^2

Given,

centre - (-3,2) = (h,k)

radius-5 units

Now as per question,

(x+3)^2+(y-2)^2=5^2

x^2+9+6x+y^2+4-4y=25

x^2+y^2+6x-4y+13=25

x^2+y^2+6x-4y=12