Question

find the equation of curve whose slope is (x-4) and which passes through the point (3,0)​

Answer 1

Step-by-step explanation:

dy/dx=x-4

dy=xdx-4dx

Integrating both sides

y=x^2/2-4x+c

and this passes through (3,0)

so, 0=9/2-12+c

c=15/2

therefore, equation is

2y=x^2-8x+15