Question

find the equation of line for which P equal to 4 and Alpha equal to 120 degree..
Answer first I will mark you as brainiest ​

Answer 1

Equation of line for which P equal to 4 and Alpha equal to 120 degree is given as :

1. P = 4 , alpha = 120°

Parametric points for these condition is

{ P.cos( alpha ) , P.sin ( alpha ) }

= ( P.cos120° , P sin120° )

= ( 4cos120° , 4sin120° )

= { 4×(-1/2) ,4×(√3)/2 }

= { (-2) , 2√3 }

2. Slope = tan ( alpha )

= tan120°

= -√3

3. Equation of line is

( y - 2√3 ) = ( -√3 ).( x + 2 )

y - 2√3 = (-√3)x - 2√3

y = (-√3)x

Answer 2

Answer:

Step-by-step explanation: WKT,

Normal form of a straight line=xcosθ+ysinθ=P

Given= P=4

            θ=120

cos(120)=cos(90+30)= -sin(30) = -1/2

sin(120)=sin(90+30)=cos(30)=√3/2

Now, substitute the values in equation,

xcos(120)+ysin(120)=P

$\frac{-x+\sqrt{3}y }{2}$=4

upon simplification we get,

x-√3y+8=0

this is the required equation.