Question

Find the equation of line going from line and point (1,-2) on line
x - 2y + 3 = 0

Answer 1

$\bold{\huge{Hay!!}}$


$\bold{Dear\:user!!}$



$\bold{\underline{Question-}}$


Find the equation of line going from line and point (1,-2) on line
x - 2y + 3 = 0


$\bold{\underline{Answer-}}$

equation of line is x - 2y +3 =0

2y = x +3

$y = \frac{1}{2} x + \frac{3}{2}$


Compareing it to y = mx + c

$m = \frac{1}{2}$

Now, the shield of perpendicular lines

$= - \frac{1}{m} = - \frac{1}{1 /2} = - 2$

Here the equation of line going from shield = -2 and point (1 , -2)

$y - y1 = - \frac{1}{m} (x - x1) \\ \\ y + 2 = - 2(x - 1) = - 2x + 2 \\ \\ y = - 2x$

Answer 2

Answer:

Step-by-step explanation:

Y= 2X