Question

Find the equation of line having slope 1/2and containing the point (3,-2)​

Answer 1

Answer:

$y=\frac{1}{2}x-\frac{7}{2}$

Step-by-step explanation:

A line which has slope of $\frac{1}{2}$ can be expressed as

$y=\frac{1}{2} x+a$.

$(x,y)=(3,-2)$

$-2=\frac{3}{2} +a$

∴$a=-\frac{7}{2}$

∴$y=\frac{1}{2}x- \frac{7}{2}$

Answer 2

Question :-

Find the equation of line having the slope 1/2 and containing the points (3,-2)

Answer :-

$\rightarrow \boxed{ \sf x - </u><u>2</u><u>y - 7 = 0} \:$

To find :-

→ Equation of line

Used formula :-

If any line having slope m and passing the points (a,b)

then equation of line is -

→ y - b = m ( x - a )

Explanation :-

Given that ,

• Slope of line (m) = 1/2

passing points (3,-2)

Hence according to the given formula

equation of line will be -

$\rightarrow \sf{ y - ( - 2) = \frac{1}{2} (x - 3)} \\ \\ \rightarrow \sf \: y + 2 = \frac{1}{2} (x - 3) \\ \\ \rightarrow \sf{2y + 4 = x - 3} \\ \\ \rightarrow \sf x - 3 - 2y - 4 = 0 \\ \\ \rightarrow \boxed{ \sf x - 2y - 7 = 0}$

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