Question

Find the equation of line having X internal = 4 Y-Interval= -3​

Answer 1

$\huge\star{\tt{\underline{\underline{\red{Answer\implies3x-4y +12=0}}}}}\star$

$\bold{\blue{\underline{Formula}}}$

$\frac{x}{a} + \frac{y}{b}$ = 1

Solution:

$\implies$ $\frac{x}{4}+ \frac{y}{-3}$ =1

$\implies$ -3x+ 4y =-12

$\implies$ $\large{\boxed{\boxed{3x-4y +12=0}}}$

Answer 2

Answer

Formula for eqⁿ of line

=>(x/a)+(y/b) =1

=>(x/4)+(y/-3)=-12

=>-3x+4y=-12

3x-4y+12=0