Question

find the equation of line L through the origin such that L and the lines x+2y-1=0 and 2x+y-1=0 are concurrent

Answer 1

Answer:

y = x

Step-by-step explanation:

x+2y-1=0

2x + 4y - 2= 0 ....(1) [Multiplying by 2]

2x+y -1= 0

-----------------

3y = 1

y = 1/3 , x = 1 - (2/3) = 1/3 (from 1)

Now,

Equation of line L will be :

(y - 1/3)/(x - 1/3) = 1

(3y-1)/(3x-1) = 1

3y-1 = 3x-1

y = x

Equations required is :

x = y

I have also attached image to help you visualise things .

Answer 2

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