The length of a wire is increased by 0.3%. Find the
percentage increase in its volume, if Poisson's
ratio of wire material is 0.5.
Answers
Answered by
26
Hi,
Answer:
The volume of the wire is increased by 0.6%.
Explanation:
Given data:
Length of the wire is increased by 0.3% therefore,
dL/L = 0.003
Poisson’s ratio of wire material, σ = 0.5
To find: percentage increase in volume
Let the volume of the wire be “V” and the change in the volume “dV”.
The increase in volume is given by
dV/V = (1 + 2 σ) dL/L
or, dV/V
= (1 + 2 * 0.5) * 0.003
= 2 * 0.003
= 0.006
Thus,
∴ Percentage increase in the volume of the wire is
= 0.006 * 100%
= 0.6 %
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