Question

find the equation of line parallel to 3x +5y=30 and passing through the intersecting point of line 2x-7y=1 and 3x+y=13.

Answer 1

from 2x-7y=1... nd 3x+y=13 ... u solve it nd will get x nd y value then 3x+5y=30... from it u should find slope (m1)...then m1=m2 ... then using straight line eqn i.e y-y1=m2(x-x1) put related value in it u get eqn