Find the equation of line passing through (0 -1) and (2 3)
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Answer: y - 2x + 1 = 0
Explanation:
Since the equation is a straight line it can be written in the form y = ax + b
Now
a = slope of the line = (y₂ - y₁)/(x₂ - x₁) = (3 - (-1))/(2 - 0) = 4/2 = 2
We can find b by substituting the values of x and y of the former mentioned point
y = ax + b
⇒ -1 = 0a + b
⇒ b = -1
Hence the required equation:
y = 2x - 1
⇒ y - 2x + 1 = 0
Hope it helped
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