Question

Find the equation of line passing through (2, - 1) with slope - 3 / 2 . Also find the angle made by the line with positive x-axis​

Answer 1

Answer:

Equation of line:   3x + 2y = 4      OR      y = -(3/2)x + 2    (same thing, just use the one that fits what you're doing in class)

Angle: -56.3° (approx)

Hope this helps.

Step-by-step explanation:

For a point (x,y) on the line, the slope from there to (2,-1) is equal to the slope of the line, so:

( y - (-1) ) / ( x - 2 ) = -3 / 2

=> 2(y+1) = -3(x-2)

=> 2y + 2 = -3x + 6

=> 3x + 2y = 4

=> y = -(3/2)x + 2

(Use whichever of the last two forms you're using in class.)

For the angle, let's call it θ.  Then

tan θ = slope of line = -3/2

=> θ = arctan (-3/2) ≈ -56.3°