Math, asked by ssangar1010, 3 months ago

Find the equation of line passing
through (3,-4) and having slop 3/2​

Answers

Answered by gyandeepkalita7
0

Answer:

y+4 = (x-3)×(3/2)

Step-by-step explanation:

y+4 = (x-3)×(3/2)

you just need to put the straight line equation formula

Answered by Anonymous
4

Answer:

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Given:Slope=

3

−5

Point is (−3,2)

Equation of the line is y−y

1

=m(x−x

1

)

y−2=

3

−5

(x+3)

⇒3y−6=−5x−15

⇒3y−6+5x+15=0

∴Equation of the line is 5x+3y+9=0

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