Find the equation of line passing
through (3,-4) and having slop 3/2
Answers
Answered by
0
Answer:
y+4 = (x-3)×(3/2)
Step-by-step explanation:
y+4 = (x-3)×(3/2)
you just need to put the straight line equation formula
Answered by
4
Answer:
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Given:Slope=
3
−5
Point is (−3,2)
Equation of the line is y−y
1
=m(x−x
1
)
y−2=
3
−5
(x+3)
⇒3y−6=−5x−15
⇒3y−6+5x+15=0
∴Equation of the line is 5x+3y+9=0
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